lim(x -> pi/6) sin(x -pi/6)/(sqrt3 -cosx...

`lim_(x -> pi/6) sin(x -pi/6)/(sqrt3 -cosx)`

lim(x -> pi/6) sin(x -pi/6)/(sqrt3 -cosx)
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lim (x rarr (pi) / (6)) (2 (sin x cos ((pi) / (6)) - cos x sin ((pi) /...
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lim (x rarr (pi) / (6)) (sin (x- (pi) / (6))) / (sqrt (3) -cos x)
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lim(x rarr pi/6)(sqrt(3)sin x-cos x)/(x-(pi)/(6))
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sin(x-pi/6)+cos(x-pi/3)=sqrt3 sinx
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Evaluate lim(xrarr(pi)/(6))((sqrt3sinx-cosx))/((x-(pi)/(6))).
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ज्ञात कीजिए : lim(xrarrpi//6) (sqrt3 sinx-cosx)/(x-(pi)/(6))
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निकालें lim(x to (pi)/(6))(sin(x-(pi)/(6)))/((sqrt3)/(2)-cosx)
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Evaluate : lim(xto(pi)/(6))(sqrt3sinx-cosx)/((x-(pi)/(6)))
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