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[" Progalsm 42.The rate constant for the...

[" Progalsm 42.The rate constant for the decomposition of "],[" hydrocarbon is "2.418times10^(-5)s^(-1)" at "546K" .If the energy of activation "],[" is "179.9kJ/mol" ,what will be the value of pre-exponential factor? "]

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The rate constant for the decomposition of hydrocarbons is 2.418 xx 10^(-5) "s"^(-1) at 546 K. If the energy of activation is 179.9" kJ mol"^(-1) , what will be the value of pre-exponential factor?

The rate constant for the decomposition of hydrocarbons is 2.418xx10^(-5)s^(-1) at 546K . If the energy of activation is 179.9kJ mol^(-1) , what will be the value of pre - exponential factor?

The rate constant for the decomposition of hydrocarbons is 2.418xx10^(-5)s^(-1) at 546K . If the energy of activation is 179.9kJ mol^(-1) , what will be the value of pre - exponential factor?

The rate constant for the decomposition of hydrocarbons is 2.418 xx 10^(-5)s^(-1) at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor.

The rate constant for the decomposition of hydrocarbons is 2.418xx10^(-5)s^(-1) as 546 K . If the energy of activation is 179.9 kJ.mol , what will be the value of pre-exponential factor ?

The rate constant for the decomposition of hydrocarbons is 2.418 x 10^(-5) (s)^(-1) at 546 (~K) . if the energy of activation is 179.9 (kJ) / (mol) , what wilt be the value of pre-exponential factor: