A light ray enters into a medium whose refractive index varies along the x-axis as `n(x) = n_(0) sqrt(1+(x)/(4))` where `n_(0)=1`. The medium is bounded by the plates `x =0,x =1` & `y =0`. It the ray enters at the origin at an angle `30^(@)` with x-axis

A system of coordinatees is drawn in a medium whose refractive index vaires as mu=(2)/(1+Y^(2)) where 0 le y le 1 . A ray of light is incident at origin at an angle 60^(@) with y-axis as shown in figure. At point P, the ray becomes parallel to x-axis, the volue of H is -

A system of coordinatees is drawn in a medium whose refractive index vaires as mu=(2)/(1+Y^(2)) where 0 le y le 1 . A ray of light is incident at origin at an angle 60^(@) with y-axis as shown in figure. At point P, the ray becomes parallel to x-axis, the volue of H is -

A system of coordinatees is drawn in a medium whose refractive index vaires as mu=(2)/(1+Y^(2)) where 0 le y le 1 . A ray of light is incident at origin at an angle 60^(@) with y-axis as shown in figure. At point P, the ray becomes parallel to x-axis, the volue of H is -

As shown in figure a ray of light in air is incident at 30^@ on a medium and proceeds ahead in the medium. The refractive index of this medium varied with distance y as given by n(y) = 1.6 + (0.2)/(y +1)^(2) where y is in cm. What is the angle formed by the ray with the normal at a very large depth ?

When a light ray enters into glass medium from water at an angle of incidence 0^(@) , what would be the angle of refraction?

A ray of light passes from vaccume into a medium of refractive index n. if the angle of incidence is twice the angle of refraction, then the angle of incidence is

Light of wavelength lambda_(0) in air enters a medium of refractive index n. If two points A and B in this medium lie along the path of this light at a distance x, then phase difference phi_(0) between these two point is