`f(x)=x^(2)+lnx`

If the function f(x)=(x^2)/2+lnx+a x is always monotonically increasing in its domain then the least value of a is 2 (b) -2 (c) -1 (d) 1

If the function f(x)=(x^2)/2+lnx+a x is always monotonically increasing in its domain then the least value of a is 2 (b) -2 (c) -1 (d) 1

y=e^(x)lnx

Consider , f(x) = x^(lnx) and g(x) = e^2x let alpha and beta (alpha lt beta) be two values of x satisfying the equation f(x)=g(x) . If h(x) = (f(x))/(g(x)) then h'(alpha) is equal to :

int x ^(x)((ln x )^(2) +lnx+1/x) dx is equal to:

Find the greatest and the least values of the following functions on the indicated intervals : f(x) = x-2lnx on [1,e]

Determine the intervals of increase and decrease for the following functions : f(x) = (2x)/("lnx")

Let C be the curve f(x)=ln^2x+2lnx and A(a,f(a)), b(b,f(b)) where (a

If f(x)=log_x(lnx) then f'(x) at x=e is

If f(x)=log_x(lnx) then f'(x) at x=e is