A, B, C are three persons among 7 persons who speak at a function. The number of waysin which it can be done if 'A' speaks before 'B' and 'B' speaks before 'C' is

A,B ,C are three persons among 7 persons who speak at a function.The number of ways in which it can be done if A speaks before B and B speaks before C is

A,B,C are three persons amongst seven persons who speak at a function . The number of ways in which it can be done if A speaks before B and B speaks before C is

Among 10 persons, A, B, C are to speak at a function. The number of ways in which it can be done if A wants to speak before B and B wants to speak before C is a. 10 !//24 b. 9!//6 c. 10 !//6 d. none of these

Among 10 persons,A,B,C are to speak at a function.The number of ways in which it can be done if A wants to speak before B and B wants to speak before C is a.10!/24b.9!/6c10!/6d d.none of these

Among 10 persons, A, B, C are to speak at a function. The number of ways in which it can be done if A wants to speak before B and B wants to speak before C is a. 10 !//24 b. 9!//6 c. 10 !//6 d. none of these

Ten persons amongst whom are A,B and C are to speak at a function the number of ways in which it can be done if A wants to speak before B and B wants to speak before C is

Ten persons, amongst whom are A, B and C are to speak at function. Find number of ways in which it can be done if A wants to speak before B, and B wants to speak before C ?

Three persons A,B,C speak at a function alongwith 7 others in a random order . The probabiltiy that A speaks before B and B speaks before C at the function is :