[" A bloek of mace "2kg" is plaed on the ter "],[" the comficient of trietion is "0.4" .A force "],[" frietion "2.5N" is appliced on the block state "],[" whe ther the block will move or not "]

A block of mass 2 kg is placed on the floor. The coefficient of friction is 0.4. If a force of 2.5 is applied on the block horizontally, what will be the state of block. Give reason.

A block of mass 2kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 2.5N is applied on the block . Calculate the force of friction between the block and the floor.

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of2.5 N is applied on the block as shown. Calculate the force of friction between the block and the floor

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4.A force F of 2.5 N is applied on the block, as shown. Calculate the force of friction between the block and the floor. ("g = 9.8 ms"^(–2))

A block of mass 2 kg is placed on the floor. The coefficient of static friction it 0.4 . A force F of 2.5 N is applied on the block, as shown. calculate the force of friction between the block and the floor. (g=9.8m//s^(2)) .

A block of mass 2kg is kept on the floor. The coefficient of static friction is 0.4 . If a force F of 2.5N is applied on the block as shown in the figure, the frictional force between the block and the floor will be.

A block of mass 2kg is kept on the floor. The coefficient of static friction is 0.4 . If a force F of 2.5N is applied on the block as shown in the figure, the frictional force between the block and the floor will be.

A block of mass 4 kg is placed on the floor. The coefficient of static friction is 0.4. If a force of 12 N is applied on the block parallel to the floor, the force of friction between the block and floor (g = 10 ms^(-2))

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 2.5 N is applied on the block as shown in Fig. 15.4.4. The force of friction between the block and the floor is (g = 9.8 m//s^(2))