If the radius of the Gaussion surface enclosing a charge q is halved, how does the electric flux through the Gaussion surface change?

If the radius of the Gaussian surface enclosing a charge is halved, how does the electric flux through the Gaussian surface change?

If the radius of gaussion surface increases, the electric flux is:

A spherical Gaussion surface encloses a charge of 8.85 * 10^-8C . Calculate the clectric flux passing through the surface.

An arbitrary surface encloses a dipole. What is the electric flux through this surface ?

An arbitrary surface encloses a dipole. What is the electric flux through this surface ?

An arbitrary surface encloses a dipole. What is the electric flux through this surface ?

A charge q is enclosed by a spherical surface of radius R. If the radius is increased to double, how would the electric flux through the surface change ?