Consider the system of equation `x+y+z=6,x+2y+3z=10 ,a n dx+2y+lambdaz=mudot` Statement 1: if the system has infinite number of solutions, then `mu=10.` Statement 2: The determinant `|1 1 6 1 2 10 1 2mu|=0formu=10.`

Consider the system of equation x+y+z=6,x+2y+3z=10 ,a n dx+2y+lambdaz=mudot Statement 1: if the system has infinite number of solutions, then mu=10. Statement 2: The determinant |(1 ,1, 6), (1, 2, 10),(1, 2,mu)| = 0 for mu=10.

Consider the system of equation x+y+z=6,x+2y+3z=10, and x+2y+lambda z=mu Statement 1: if the system has infinite number of solutions,then mu=10. Statement 2: The determinant det[[1,2,101,2,101,2,mu]]=0 for mu=10

Consider the system of equation x+y+z=6,x+2y+3z=10 ,a n dx+2y+lambdaz=mudot then show that Statement 1: if the system has infinite number of solutions, then mu=10. Statement 2: The determinant |(1 ,1, 6), (1, 2, 10),(1, 2,mu)| = 0 for mu=10.

Given a system of equations in x,y,z : x+y+z=6,x+2y+3z=10 and x+2y+az=b . If this system has infinite number of solutions, then a^(2)+b= ……….

Given a system of equations in x,y,z : x+y+z=6,x+2y+3z=10 and x+2y+az=b . If this system has infinite number of solutions, then a^(2)+b= ……….

Consider the system of the equation k x+y+z=1,x+k y+z=k ,a n dx+y+k z=k^2dot Statement 1: System equations has infinite solutions when k=1. Statement 2: If the determinant |1 1 1k k1k^2 1k|=0, t hen k=-1.

Consider the system of the equation k x+y+z=1,x+k y+z=k ,a n dx+y+k z=k^2dot Statement 1: System equations has infinite solutions when k=1. Statement 2: If the determinant |1 1 1k k1k^2 1k|=0, t hen k=-1.

Consider the system of the equation k x+y+z=1,x+k y+z=k ,a n dx+y+k z=k^2dot Statement 1: System equations has infinite solutions when k=1. Statement 2: If the determinant |1 1 1k k1k^2 1k|=0, t hen k=-1.

Consider the system of equations x+y+z=6 x+2y+3z=10 x+2y+lambdaz =mu the system has infinite solutions if

Consider the system of equations x+y+z=6 x+2y+3z=10 x+2y+lambdaz =mu the system has infinite solutions if