tan(alpha-beta)+tan(beta-gamma)+tan(sin alpha)

tan(alpha-beta)+tan(beta-alpha)+tan(gamma-alpha)=tan(alpha-beta)tan(beta-gamma)tan(gamma-alpha) Reason (R):In Delta ABC sum tan A=pi tan A

Prove that: tan(alpha-beta)+tan(beta-gamma)+tan (gamma-alpha) = tan(alpha-beta) tan (beta-gamma) tan (gamma-alpha) .

If alpha,beta,gamma are three distinct real numbers such than 0

Prove that: (tan(alpha-beta)+tan(beta-lambda)+tan(lambda-alpha) = tan(alpha-beta)tan(beta-lambda)tan(lambda-alpha)

If alpha + beta + gamma = pi , show that : tan (beta+gamma-alpha) + tan (gamma+alpha-beta) + tan (alpha+beta-gamma) = tan (beta+gamma-alpha) tan (gamma+alpha-beta) tan (alpha+beta-gamma)

If alpha + beta + gamma = pi , show that : tan (beta+gamma-alpha) + tan (gamma+alpha-beta) + tan (alpha+beta-gamma) = tan (beta+gamma-alpha) tan (gamma+alpha-beta) tan (alpha+beta-gamma)

If (tan(alpha + beta - gamma))/(tan(alpha - beta + gamma)) = (tan gamma)/(tan beta), (beta ne gamma) , then sin 2alpha + sin 2beta + sin 2gamma=

If alpha+beta+gamma=2pi, then (a) tan(alpha/2)+tan(beta/2)+tan(gamma/2)=tan(alpha/2)tan(beta/2)tan(gamma/2) (b) tan(alpha/2)tan(beta/2)+tan(beta/2)tan(gamma/2)+tan(gamma/2)tan(alpha/2)=1 (c) tan(alpha/2)+tan(beta/2)+tan(gamma/2)=-tan(alpha/2)tan(beta/2)tan(gamma/2) (d)none of these