[" Calculate "Lambda_(m)^( oo)" of oxalic acid,given that "],[qquad [Lambda_(eq)^( oo)Na_(2)C_(2)O_(4)=400Omega^(-1)cm^(2)eq^(-1)],[Lambda_(m)^( oo)H_(2)SO_(4)=700Omega^(-1)cm^(2)mol^(-1)],[Lambda_(eq)^( oo)Na_(2)SO_(4)=450Omega^(-1)cm^(2)eq^(-1)]]

Calculate lamda_(m)^(0) of oxalic acid, given that lamda_(eq)^(0)Na_(2)C_(2)O_(4)=400Omega^(-1)cm^(2)aq^(-1) lamda_(m)^(0)H_(2)SO_(4)=700Omega^(-1)cm^(2)"mole"^(-1) lamda_(eq)^(0)Na_(2)SO_(4)=450Omega^(-1)cm^(2)eq^(-1)

Calculate lamda_(m)^(0) of oxalic acid, given that lamda_(eq)^(0)Na_(2)C_(2)O_(4)=400Omega^(-1)cm^(2)aq^(-1) lamda_(m)^(0)H_(2)SO_(4)=700Omega^(-1)cm^(2)"mole"^(-1) lamda_(eq)^(0)Na_(2)SO_(4)=450Omega^(-1)cm^(2)eq^(-1)

Calculate Lambda_(m)^(oo) for acetic acid, given, Lambda_(m)^(oo)(HCl)=426 Omega^(-1)cm^(2)mol^(-1),Lambda_(m)^(oo)(NaCl)=126Omega^(-1)cm^(2)mol^(-1) , Lambda_(m)^(oo)(CHCOONa)=91Omega^(-1)cm^(2)mol^(-1)

From the following molar conductivities at infinite dilution. Lambda_(m)^(@) for Ba(OH)_(2) = 457.6 Omega^(-1) cm^(2) "mol"^(-1) Lambda_(m)^(@) for BaCl_(2) = 240.6 Omega^(-1) cm^(2) "mol"^(-1) Lambda_(m)^(@) for NH_(4) Cl = 129.8 Omega^(-1) cm^(2) "mol"^(-1) Calculate Lambda_(m)^(@) for NH_(4) OH .

Lambda_(ClCH_(2)COONa)^(@)=224 Ohm^(-1)cm^(2)g meq^(-1), Lambda_(NaCl)^(@)=38.2Ohm^(-1)cm^(2)gm eq^(-1), Lambda_( HCl)^(@)=203Ohm^(-1)cm^(2)gm eq^(-1) . What is the value of L_(ClCH_(2)COOH)^(@) ?