Find the value of `n` if `2n+1,n^(2)+n+1,3n^(2)-3n+3` are consecutive terms of an AP

Find the value of n , if (2n - 1)/(n - 2) = 3

Find the value of (3^n × 3^(2n + 1))/(3^(2n) × 3^(n - 1))

Find the value of n if ""^(2n+1)P_(n-1):""^(2n-1)P_n=3:5 .

Find the value of (3^(n)xx3^(2n+1))/(9^(n)xx3^(n-1)) .

If the sum of n terms of an A.P is (4n^(2)-3n)/(4) then ,n^(th) term of the A.P

In the sequence 1, 2, 2, 3, 3, 3, 4, 4,4,4,....., where n consecutive terms have the value n, the 150 term is

The sum of first n terms of an AP is given by S_(n)=2n^(2)+3n. Find the sixteenth term of the AP.

Find the sum of 1^1 n + 2^2 (n - 1) + 3^2 (n - 2) + 4^2 (n -3) ……upto 'n' terms.

In the sequence 1,2,2,3,3,3,4,4,4,4,..., where n consecutive terms have the value n, the 150 term is

The sum of first n terms of an AP is (3n^2+6n) Find the n^(th) term and 15^(th) terms of the AP