If `tan^2alpha+2tanalpha.tan2beta=tan^2beta+2tanbeta.tan2alpha` then

If tan^(2) alpha+ 2tan alpha tan 2 beta= tan^(2) beta+ 2 tan beta tan 2 alpha, show that tan beta=+- tan alpha .

tan^2 alpha+2tan alpha.tan2beta=tan^2 beta+2tan beta.tan2 alpha, if (A) tan^2 alpha+2tan alpha.tan2beta=0 (B) tan alpha+tan beta=0 (C) tan^2 beta+2tanbeta,tan2 alpha=1 (D) tan alpha=tan beta

If tan^2 alpha tan^2 beta + tan^2 beta tan^2 gamma + tan^2 gamma tan^2 alpha + 2 tan^2 alpha tan^2 beta tan^2 gamma = 1 then sin^2 alpha + sin^2 beta + sin^2 gamma =

If tan^2 alpha tan^2 beta + tan^2 beta tan^2 gamma + tan^2 gamma tan^2 alpha + 2 tan^2 alpha tan^2 beta tan^2 gamma = 1 then sin^2 alpha + sin^2 beta + sin^2 gamma =

If tanalpha=(1-cosbeta)/(sinbeta),t h e n (a) tan3alpha=tan2beta (b) tan2alpha=tanbeta (c) tan2beta=tanalpha (d) none of these

If 2 tan^2 alpha tan^2 beta tan^2 gamma+ tan^2 alpha tan^2 beta+ tan^2 beta tan^2 gamma+ tan^2 gamma tan^2 alpha=1 , prove that sin^2 alpha+ sin^2 beta+ sin^2 gamma =1 .

If tan^(2)alpha tan^(2)beta+tan^2betatan^(2)lamda+tan^(2)lambdatan^(2)alpha+2tan^(2)alpha tan^(2) beta tan^(2)lamda = 1 then sin^2alpha+sin^2beta+sin^2lamda =

Let alpha,beta,gamma > 0 and alpha+beta+gamma=pi/2. Statement-1: |tan alpha tan beta-(a!)/6|+|tan beta tan gamma-(b!)/2|+|tan gamma tanalpha-(c!)/3| le 0, where n! =1.2..........n, then tan alpha tanbeta,tanbeta tangamma, tan gamma tan alpha=1 Settlement 2 : tan alpha tanbeta+,tanbeta tangamma+, tan gamma tan alpha=1

Let alpha,beta,gamma > 0 and alpha+beta+gamma=pi/2. Statement-1: |tan alpha tan beta-(a!)/6|+|tan beta tan gamma-(b!)/2|+|tan gamma tanalpha-(c!)/3| le 0, where n! =1.2..........n, then tan alpha tanbeta,tanbeta tangamma, tan gamma tan alpha=1 Settlement 2 : tan alpha tanbeta+,tanbeta tangamma+, tan gamma tan alpha=1

If tan alpha=(1-cos beta)/(sin beta), then a )tan3 alpha=tan2 beta(b)tan2 alpha=tan beta(c)tan2 beta=tan alpha(d) none of these