If `(sec A + tan A) (sec B + tan B) (sec C + tan C) = (sec A-tan A) (sec B-tan B) (sec C-tan C)` then each side is equal to

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If (sec A + tan A)(sec B + tan B)(sec C + tan C) = (sec A- tan A)(sec B- tan B)(sec C tan C) Prove that each side is equal to +-1.

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If k=( sec A + tan A) ( sec B+ tan B) sec C + tan C)=(sec A - tan A)(sec B- tan B)(sec C - tan C) " then " k=

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1/(sec A + tan A) = sec A - tan A

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(1)/(sec A-tan A)=sec A+tan A

If (tan A + sec A) (tan B + sec B) (tan C + sec C) = (tan A -sec A) (tan B -secB) (sec C-tan C),show that each side is equal to +-1