[" 12.If "4n6=pi" ,then "],[qquad sin^(2)theta+sin^(2)3 theta+sin^(2)5 theta+sin2n" terms is equal to "]

Prove that sin^(3)theta+sin^(3)3 theta+sin^(3)5 theta+....+n terms is equal to

If 4n theta=pi, then sin^(2)theta+sin^(2)3 theta+sin^(2)5 theta+....2n terms is equal to: (1)n,(2)2n*(3)3n(4)n^(2)

If 4n theta = pi , then sin^2 theta+ sin^2 3theta + sin^2 5theta +.... 2n terms is equal to:(1) n , (2) 2n . (3) 3n (4) n^2

If sin 6theta = sin 4theta - sin 2theta , then theta =

Express sin^(5)theta in term of sin ( n theta), n in N .

Express sin^(5)theta in term of sin ( n theta), n in N .

2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta) is equal to