lim(x->0)(sinx+log(1-x))/(x^2)...

`lim_(x->0)(sinx+log(1-x))/(x^2)`

lim(x->0)(sinx+log(1-x))/(x^2)
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lim(x->0)(e^log(2^x-1)^x-(2^x-1)^(x)*sinx))/(e^(xlogx)) is equal to
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Evaluate lim(x to 0) (sinx+log(1-x))/(x^(2)).
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Prove that:lim(x rarr 0) (log(1+x)+sinx)/(e^(x)-1)=2
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Prove that:lim(x to0)log(1+sinx)/(x)=1
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Evaluate: lim(x rarr 0) ((e^(2)-1)log(1+x))/(sinx)
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The value of [lim(x to 0)((sinx)/(x))^(sinx/(x-sinx))+lim(x to 1)x^(1/...
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lim(x to 0)[(1/x)-log(1+x)/x^2]
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প্রমাণ করো, lim(x to 0) (log(1+x)+sinx)/(e^x-1) = 2
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