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From the focus of parabola y^2 = 8x as c...

From the focus of parabola `y^2 = 8x` as centre, a circle is described so that a common chord is equidistant from vertex and focus of the parabola. The equation of the circle is

Text Solution

Verified by Experts

OP=PF
OP=OF/2=1
`y^2=8x`
`y^2=8`
`y=pm2sqrt2`
`FN=sqrt((2-1)^2+(2sqrt2-0)^2)=sqrt9=3`
Circle=`(x-2)^2+y^2=9`.
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