[" [Hint: Write the expression the "],[(1+sec A)/(sec A)=(sin^(2)A)/(1-cos A)quad " (Hint: Simplify LHS and RHS separt "],[cos A-sin A+1=csc A+cot A" ,using the identity cose "]

(cos A-sin A+1)/(cos A+sin A-1)=cosec A+cot A," using the identity cosec^(2)A=1+cot

Prove the following identities. where the angles involved are acute angles for which the expressions are defined. (1+secA)/(secA)=(sin^(2)A)/(1-cosA) [Hint: Simplify LHS and RHS separately]

( cos A - sin A + 1 ) / ( cos A + sin A - 1 ) = cosec A + cot A cosec A + cot A , = using the identity cosec ^ 2 A = 1 + cot^ 2 A .

(cos A-sin A + 1) / (cos A + sin A-1) = csc A + cot A

Prove that (sec A-1)/(sec A+1)=((sin A)/(1+cos A))^(2)=(cot A-cos ecA)^(2)

Prove the following identities : cosec A - cot A = (sin A)/ (1 + cos A)

Prove that: (cosec A-sin A)(sec A-cos A)=(1)/(tan A+cot A)

(sin A)/(sec A+tan A-1)+(cos A)/(cos ecA+cot A-1)=1

Prove that : (tan A + cot A) (cosec A - sin A) (sec A - cos A) = 1

Prove the following identity,where the angles involved are acute angles for which the expressions are defined.( ix) (csc A-sin A)(sec A-cos A)=(1)/(tan A+cot A)[ Hint : Simplify L.HS and RHS separately]