x-(y)/(5)-10=0

Find the solution of the pair of equations (x)/(10) + (y)/(5) - 1 = 0 and (x)/(8) + (y)/(6) = 15 and find lambda , if y = lambda x + 5 .

Find the solution of the pair of equations (x)/(10) + (y)/(5) - 1 = 0 and (x)/(8) + (y)/(6) = 15 and find lambda , if y = lambda x + 5 .

Find x,y,p,q if [(2x-y,5,5p+2q),(p+2q,x-2y,-10)]=[(0,5,7),(3,-3,-10)]

A=[[x,5y2x,0]] and B=[[0,(y)/(2)(x)/(5),-(y)/(10)]] find AB

The length of the diameter of the circle which cuts three circles : x^2+y^2-x-y-14=0 x^2+y^2+3x-5y- 10=0 x^2+y^2-2x+3y-27=0 orthogonally, is :

The length of the diameter of the circle which cuts three circles x^(2)+y^(2)-xy-14=0 x^(2)+y^(2)+3x-5y-10=0 x^(2)+y^(2)-2x+3y-27=0 M orthogonally, is

5x-2y-10=0,10x-4y-20=0 these are………lines.

If the lines 12x + 5y + 16 = 0 and 12 x+ 5y - 10 = 0 are tangent to a circle then the radius is :

For the plane prod=2x+3y+5z+10=0 , the point (2,3,-5) lies in the