[" Consider the junction diode is ideal.The value of current through the resistance of "300Omega" is "],[qquad [(4v)/(300Omega),-1V," 4et "]],[[(-4V)/(300Omega),-1,24=]],[]

Consider the junction diode is ideal. The value of current through the resistance of 300 Omega is

Consider the junction diode is ideal. The value of current through the resistance of 300 Omega is

Consider the junction diode is ideal. The value of current through the resistance of 200 Omega is

Assuming that the silicon diode having resistance of 20 Omega , the current through the diode is (knee voltage 0.7 V)

4 ideal diodes are connected as shown in the circuit the current through 50 Omega is. .

A 4 V battery of internal resistance 1 Omega sends a current through a 3 Omega resistor. The terminal p.d. is

Two cells of emf 2V and 4V and internal resistance 1Omega and 2Omega respectively are connected in parallel so as to send the current in the same direction through an external resistance of 10Omega. Find the potential difference across 10Omega resistor.

Two cells of emf 2V and 4V and internal resistance 1Omega and 2Omega respectively are connected in parallel so as to send the current in the same direction through an external resistance of 10Omega . Find the potential difference across 10Omega resistor.