[" (d) "K^(+)

A parallel plate capacitor is made of two dielectric blocks in series. One of the blocks has thickness d_(1) and dielectric constant k_(1) and the other has thickness d_(2) and dielectric constant k_(2) as shown in figure. This arrangement can be thought as a dielectric slab of thickness d = ( d_(1) + d_(2) ) and effective dielectric constant k. The k is ...... (a) (K_(1)d_(1)+K_(2)d_(2))/(d_(1)+d_(2)) (b) (K_(1)d_(1)+K_(2)d_(2))/(K_(1)+K_(2)) (c) (K_(1)K_(2)(d_(1)+d_(2)))/((K_(1)d_(2)+K_(2)d_(1))) (d) (2K_(1)K_(2))/(K_(1)+K_(2))

A + B rarr Product, (d x)/(d t) = k[A]^(a)[B]^(b) If ((d x)/(d t)) = k , then order is:

vec(i)timesvec(j)= (a) vec0 (b) 1 (c) -vec k (d) vec k

A parallel plate capacitor is made of two square plates of side 'a' , separated by a distance d much less than a. The lower triangular portion is filled with a dielectric of dielectric constant K, as shown in the figure. Capacitance of this Capacitor is : a) (Kin_(0)a^(2))/(2d(K+1)) b) (Kin_(0)a^(2))/(d(K-1)) In K c) (Kin_(0)a^(2))/(d)In K d) (1)/(2)(Kin_(0)a^(2))/(d)

If a = I + j + k, b = I + j - k, c = I - j + k, d = I - j - k then (a xx b). (c xx d) =

If x=log_(k)b=log_(b)c=(1)/(2)log_(c)d, then log_(k)d is equal to

If A=[[a,bc,d]] (where bc!=0 ) satisfies the equations x^(2)+k=0, then a+d=0, b.K=-|A| c.k=|A|d .none of these

The vitamins A,D,E,K are ___soluble vitamins.