[" Let "omega" be a complex cube root of unity with "omega!=],[" 1.A fair die is thrown three times.If "r_(1),r_(2)],[" and "r_(3)" are the numbers obtained on the die,then "],[" the probability that "omega^(r_(1))+omega^(r_(2))+omega^(r_(3))=0" is - "]

Let omega be a complex cube a root of unity with omega != 1 . A fair die is thrown three times . If r_(1),r_(2) and r_(3) are the numbers obtained on the die , then the probability that omega^(r_(1))+omega^(r_(2))+omega^(r_(3))= 0 is :

Let omega be a complex cube root of unity with omega ne 1 . A fair die is thrown three times. If r_(1), r_(2) and r_(3) are the numbers obtained on the die, then the probability that omega^(r_(1)) + omega^(r_(2)) + omega^(r_(3)) = 0 is

Let omega be a complex cube root unity with omega != 1. A fair die is thrown three times. If r_1,r_2 and r_3 are the numbers obtained on the die, then the probability that omega^(r1) + omega^(r2) + omega^(r3)=0 is (a) 1/18 (b) 1/9 (c) 2/9 (d) 1/36

Let omega be a complex cube root unity with omega!=1. A fair die is thrown three times. If r_1, r_2a n dr_3 are the numbers obtained on the die, then the probability that omega^(r1)+omega^(r2)+omega^(r3)=0 is 1//18 b. 1//9 c. 2//9 d. 1//36

Let omega be a complex cube root unity with omega!=1. A fair die is thrown three times. If r_1, r_2a n dr_3 are the numbers obtained on the die, then the probability that omega^(r1)+omega^(r2)+omega^(r3)=0 is 1//18 b. 1//9 c. 2//9 d. 1//36

Let omega be a complex cube root unity with omega!=1. A fair die is thrown three times. If r_1, r_2a n dr_3 are the numbers obtained on the die, then the probability that omega^(r1)+omega^(r2)+omega^(r3)=0 is 1//18 b. 1//9 c. 2//9 d. 1//36

Let omega be a complex cube root unity with omega!=1. A fair die is thrown three xx.If r_(1),r_(2) and r_(3) are the numbers obtained on the die,then the probability that omega^(r1)+omega^(r2)+omega^(r3)=0 is (a) (1)/(18) (b) (1)/(9)(c)(2)/(9) (d) (1)/(36)