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Let f(x) be defined in the interval [-2,...

Let f(x) be defined in the interval [-2,2] such that `f(x) = { -1; -2<= x <= 0} and f(x) = {x-1 ; 0 < x <=2}` and `g(x) = f(|x|) + |f(x)|`, The number of points where g(x) is not differentiable in (-2,2), is

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g(x)=f(|x|)+|f(x)|
g(x)=-x-1+1
=-x-1+1-x
=x-1+x-1
g(x)=-x
=0
=2x-2
option b is correct.
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