The lines `2x-3y-5=0` and `3x-4y=7` are diameters of a circle of area `154(=49 pi)` sq. units, then the equation of the circle is

If the lines 2x-3y-5=0 and 3x-4y=7 are diameters of a circle of area 154 sq. units, then the equation of the circle is

Choose the correct alternative.If the lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 sq. units then the equation of such a circle is….

The lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 sq. units. Then the equation of the circle is

The lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 sq. units. Then the equation of the circle is

The lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 sq. units. Then the equation of the circle is a. x^(2)+y^(2)+2x-2y-62=0 b. x^(2)+y^(2)+2x-2y-47=0 c. x^(2)+y^(2)-2x+2y-62=0 d. x^(2)+y^(2)-2x+2y-47=0

The lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 sq. units. Then the equation of the circle is x^2+y^2+2x-2y=62 x^2+y^2+2x-2y=47 x^2+y^2-2x+2y=47 x^2+y^2-2x+2y=62

The lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 sq.units. Then the equation of the circle is x^(2)+y^(2)+2x-2y=62x^(2)+y^(2)+2x-2y=47x^(2)+y^(2)-2x-2y=47x^(2)+y^(2)-2x+2y=62

The lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 sq. units. Then the equation of the circle is (a) x^2+y^2+2x-2y=62 (b) x^2+y^2+2x-2y=47 (c) x^2+y^2-2x+2y=47 (d) x^2+y^2-2x+2y=62