What is the angle between the plane of polariser and that of analyser to reduce the transmitted light intensity to half ?

The angle between the plane of polarisation and the direction of propagation of the polarised light is

The unpolarised light is incident on polarisers placed above the other, so what is the angle between these two polarisers so that the than the intensity of the transmitted light is (1)/(3) than the intensity of incident light?

The angle between the plane of oscillation and plane of polarisation of the polarised light is

What is the angle of between the plane of polarisation and the direction to propagation to polarised light?

If the angle between the pass axes of a polariser and analyser is 45^@ . Write the ratio of the intensities of original light and the transmitted light after passing through the analyser.

If theta is the angle between the transmission axes of the polarizer and the analyser and l_0 be the intensity of the polarized light incident on the analyser, then Intensity of transmitted light through analyser would be