From two identical holes, nitrogen and an unknown gas are leaked into a common vessel of `3 L` capacity for `10 min`, at `27^(@)C`. The resulting pressure is `4.18` bar and the mixture contains `0.4 mol` of nitrogen. What is the molar mass of the unknown gas?

For 10 minutes each, at 27^@C , from two identical holes nitrogen and an unknown gas are leaked into a common vessel of 3 litre capacity. The resulting pressure is 4.18 bar and the mixture contains 0.4 mole of nitrogen. What is the molar mass of the unknown gas ?

For 10 minutes each at 27^(@)C from two identical holes nitrogen and an unknow gas are leaked into a common vessel of 3 litre capacity The resulting pressure is 4.18 bar and the mixture contains 0.4 mole of nitrogen What is the molar mass of the unknown gas ? .

For 10 minutes each, at 0^(@)C , from two identical holes nitrogen and an unknown gas are leaked into a common vessel of 4 litre capacity. The resulting pressure is 2.8 atm and the mixture contains 0.4 mole of nitrogen. What is the molar mass of unknown gas ? (Take R = 0.821 "L-atm mol"^(-1)K^(-1) ]

For 10 minutes each, at 0^(@)C , from two identical holes nitrogen and an unknown gas are leaked into a common vessel of 4 litre capacity. The resulting pressure is 2.8 atm and the mixture contains 0.4 mole of nitrogen. What is the molar mass of unknown gas ? (Take R = 0.821 "L-atm mol"^(-1)K^(-1) ]

The constant motion and high velocities of gas particles lead to some important practical consequences One such consequence is that is mixing rapidly when they come in contact. The mixing of different gases by random molecular motion and with frequent collisions is called diffusion.A similar process in which gas molecules escape through a tiny hole into vaccum is called effusion. For 10 min each at 27^(@) C from two identical bulbs helium and an unknown gas X at equal pressure are leaked into a common vessel of 3L capacity. The resulting pressure is 4.1 atm and the mixture contains 0.4 mol of helium The molar mass of gas X is