The wavelength of the first line in blamer series in the hydrogen spectrum is `lambda`. What is the wavelength of the second line:

Calculate the wavelength of the first line in the balmer series of hydrogen spectrum

The wavelength of the second line of balmer series in the hydrogen spectrum is 4861A^(@) .the wavelength of the first line is ?

Calculate the wavelength of the first line in the Balmer series of hydrogen spectrum

The wavelength of the first line of Balmer series of hydrogen atom is lambda , the wavelength of the same line in doubly ionised lithium is

The wavelength of the second line of the balmer series in the hydrogen spectrum is 486 1 Å . Calculate the wavelength of the first line

Calculate the wavelength of the first line in the Balmer series of hydrogen spectrum.

The wavelength of the first line of the Balmer series of hydrogen atom is lamda . The wavelength of the corresponding line line of doubly ionized lithium atom is

The Wavelength of first member of Balmer series in hydrogen spectrum is lambda . Calculate the wavelength of first member of Lymen series in the same spectrum