If (4, 1) be an end of a diameter of the circle `x^2 + y^2 - 2x + 6y-15=0`, find the coordinates of the other end of the diameter.

One end of a diameter of the circle x^2+y^2-3x+5y-4=0 is (2,1). Find the coordinates of the other end.

If one end of a diameter of the circle x^(2) + y^(2) -4x-6y +11=0 is (3, 4), then find the coordinates of the other end of the diameter.

If one end of a diameter of the circle x^(2) + y^(2) -4x-6y +11=0 is (3, 4), then find the coordinates of the other end of the diameter.

If one end of a diameter of the circle x^(2)+y^(2)-4x-6y+11=0 is (3, 4), then find the coordinates of the other end of the diameter.

If one end of a diameter of the circle x^(2) + y^(2) - 4x - 6y + 11 = 0 is (3, 4), then the coordinates of the other end of the diameter are

If one end a diameter of the circle x^(2) + y^(2) - 4x - 6y + 11 = 0 is (3,4), then find the cordinate of the other end of the diameter.

One end of a diameter of the circle x^(2) + y^(2) = 2 is (1,-1) . Then coordinates of its other end is

The coordinaters of one end of a diameter of a circle x^(2)+y^(2)-8x-4y+15=0 is (2,1). Find the coordinates of the other end of the diameter.

If one end of the diameter of the circle x^2+y^2-2x+6y-3=0 is (+4,-5) , find the co-ordinates of the other end.