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cos(60^0-theta)cos(6 0^(@)+theta)=1/4(4c...

`cos(60^0-theta)cos(6 0^(@)+theta)=1/4(4cos^2theta-3)`

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Prove that cos thetacos(60^(@)- theta)cos(60^(@)+theta) = 1/4 cos 3 theta

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