x और y के लिये हल कीजिए :
`2^(y-x)(x+y)= 1` और `(x+y)^(x-y) = 2`

Explanation

यहाँ
`2^(y-x)(x+y) = 1" "rArr" "x + y= (1)/(2^(y-x))`
`rArr" "x+y = 2^(x-y)" ".....(1)`
और `" "(x+y)^(x-y) = 2" ".....(2)`
`rArr" "(2^(x-y))^(x-y) = 2`
`rArr" "2^((x-y)^(2)) = 2^(1)`
`rArr" "(x-y)^(2) = 1`
`rArr" " x - y = pm 1`
यदि x - y = 1 तो x + y =2
हल करने पर `x =(3)/(2), y = (1)/(2)`
यदि x - y = - 1 तो `(x +y)^(-1) = 2`
अतः `x - y = - 1`
और `x + y = (1)/(2)`
हल करने पर
`x = - (1)/(4), y = (3)/(4)`
`therefore {:(x=(3)/(2)),(y = (3)/(4)):}}`या` {:(x=-(1)/(4)),(y = (3)/(4)):}}`