यदि `27^(@)C` ताप तथा 2 bar दाब पर एक गैस का घनत्व `5.46 dm^(-3)` है तो इसका STP पर घनत्व क्या होगा ?

Explanation

`because m = (dRT)/(P)`
`therefore d = (mP)/(RT)`
`therefore d prop (P)/(T)" " (because` गैस के लिये m तथा R स्थिर है )
`therefore (d_(1))/(d_(2)) = (P_(1)xx T_(2))/(P_(2) xx T_(1))`
`therefore d_(2) = (d_(1)xxP_(2)xxT_(1))/(P_(1)xxT_(2))`
`d_(1) = 5.46 g dm^(-3),P_(1) = 2 "bar", T_(1) = 300 K`
STP पर, `d_(2) = ?, P_(2) = "bar", T_(2) 273`
`therefore d_(2) = (5.46 xx 1 xx 300)/(2xx 273) = 3.0 g dm^(-3)`