हाइड्रोजन का rms वेग 300 K पर `1.9 xx10^(3)ms^(-1)` है, तो ऑक्सीजन का rms वेग 1200 K पर होगा :

Options

A. `7.6 xx 10^(3) ms^(-1)`
B. `3.8xx 10^(3) ms^(-1)`
C. `0.95xx 10^(3) ms^(-1)`
D. `0.475xx10^(3) ms^(-1)`

Answer

C

Explanation

`because u_(rms) = sqrt((3RT)/(M))`
`therefore u_(H_(2)) = sqrt((3R xx 300)/(2)) = 1.9xx10^(3)`
`therefore u_(O_(2)) = sqrt((3RTxx1200)/(32)) = (2)/(4) sqrt((3R xx 300)/(2))`
` = (2)/(4) xx 1.9 xx 10^(3) = 0.95 xx 10^(3) ms^(-1)`