निचे दिए गए उष्मीय रसायन आंकड़ों के अनुसार, `Delta_(f)G_(H^+))^@(aq)=0`
`H_(2)O(l)toH^(+)(aq)+OH^(-)(aq),DeltaH=57.32kJ`
`H_(2)(g)+1/2O_(2)(g)to H_(2)O(l)," "H_(2)O(l)," "DeltaH=-268.20kl`
`25^@C` पर `OH^(-)` आयाज के सम्भव की एन्थेलपी का मान है ,

Options

A. `-22.88 kJ`
B. `-228.88 kJ`
C. `+228.88 kJ`
D. `-343.52 kJ`

Answer

B

Explanation

`H_(2)O(l)toH^(+)(aq*)+OH^(-)(aq*), " "DeltaH=57.32 kJ" ...(1)"`
`H_(2)(g)+1/2O+_(2)toH_(2)O(l)," "DeltaH=-281.20 kJ" ...(2)"`
समी० (1) व् (2) को जोड़ने पर,
`H_(2)(g)+1/2O_(2)(g)to H^(+)(aq*)+OH^(-)(aq*)," "DeltaH=-228.88kJ`
`because" "Delta_(f)H^(@)H^(+)=0`
`:." "Delta_(f)H^(@)OH^(-)=-228.88 kJ`