अभिक्रिया `X_2O_(4)(l)to 2XO_(2)(g)` के लिए 300K पर `DeltaU=2.1` kcal, `DeltaS=20" cal K"^-1` , है तो `DeltaG` होगा:

Options

A. `9/3` kcal
B. `-9.3` kcal
C. `2.7` kcal `
D. `-2.7` kcal

Answer

D

Explanation

`:." "DeltaH=DeltaU+Deltan_(g)"RT"` से,
`DeltaH=2.1xx10^(3)+2xx2xx300`
`=3.3"kcal "(becaue Deltan_(g)=2-0=2)`
अब `DeltaG=DeltaT-TDeltaS` से,
`DeltaG=3.3xx10^(3)-330xx20`
`= 2.7"kcal"`