यदि `tan(theta_(1)+theta_(2))=(tan theta_(1)+tan theta_(2))/(1-tantheta_(1)tan theta_(2)), theta_(1)` व `theta_(2)` न्यूनकोण है तब `theta_(1)+theta_(2)` का मान ज्ञात कीजिए यदि `tan theta_(1)=1/2` व `tan theta_(2)=1/3`

Explanation

दिया है `tan (theta_(1)+theta_(2))=(tan theta_(1)+tan theta_(2))/(1-tan theta_(1)tan theta_(2))`
`(1/2+1/3)/(1-1/2xx1/3)=((3+2)/(6))/(1-1/6)=(5/6)/(5/6)=1" "(because tan theta_(1)=1/2` व `tan theta_(2)=1/2)`
`impliestan(theta_(1)+theta_(2))=1impliestheta_(1)+theta_(2)=45^(@)`