`(sin (90^(@)+theta)sin (180^(@)-theta)tan (180^(@)-theta))/(cos (90^(@)-theta)cos (180^(@)-theta)tan (180^(@)+theta))` का मान ज्ञात कीजिए.

Options

A. `0`
B. `2`
C. `1`
D. `1/2`

Answer

C

Explanation

हम जानते है कि
`sin (90^(@)+theta)=cos theta`
`sin (180^(@)-theta)=sin theta`
`tan (180^(@)-theta)=-tan theta`
`cos (90^(@)-theta)=0cos theta`
`tan (180^(@) +theta)=tan theta`
उपरोक्त सम्बन्धो का प्रयोग करने पर
`(sin (90^(@)+theta)cos (180^(@)-theta)tan (180^(@)-theta))/(cos (90^(@)-theta)cos (180^(@)-theta)tan(180^(@)+theta))=(cos thetasin theta(-tan theta))/(sin theta(-cos theta)tan theta)=(-1)/(-1)=1`