यदि `sin theta-cos theta=1/2,` तब `(1)/(sin theta+cos theta)` का मान ज्ञात कीजिए.

Explanation

यहाँ `sin theta -cos theta =1/2 implies(sin theta-cos theta)^(2)=((1)/(2))^(2)`
` implies2sin theta*cos theta=3/4" "...(1)`
अब, `(sin theta+cos theta)^(2)=sin^(2)theta+cos ^(2)theta+2 sin theta cos theta=1+3/4`
`implies(sintheta+cos theta)=sqrt((7)/(4))`
`implies(1)/(sin theta+cos theta)=(2)/(sqrt7)=(2sqrt7)/(7)*`