Illuminating the surface of a certain metal alternatrly with light of wavelengths `lambda_(1) = 0.35 mu m` and `lambda_(2) = 0.54 mu m`, it was found that the corresponding maximum velocities of photoelectrons differ by a factor `eta = 2.0`. Find the work function of taht metal.

Illuminating the surface of a certain metal alternatively with light of wavelength lambda_(1)=0.35 mu m and lambda_(2)=0.54 mu m , it was found that the corresponding maximum velocities of photo electrons have a ratio eta=12 . Find the work function of that metal.

Illuminating the surface of a certain metal alternately with light of wavelengths lambda_(1)=0.35 mu m and lambda-(2) =0.54 pm , it was found that the corresponding maximum velocities of photo electrons have a ratio eta = 2. Find the work function of that metal:

Surface of certain metal is first illuminated with light of wavelength lambda_(1)=350 nm and then, by light of wavelength lambda_(2)=540 nm. It is found that the maximum speed of the photo electrons in the two cases differ by a factor of 2. The work function of the metal (in eV) is close to : (Energy of photon =(1240)/(lambda("in nm"))Ev

Surface of certain metal is first illuminated with light of wavelength lambda_(1)=350 nm and then, by light of wavelength lambda_(2)=540 nm. It is found that the maximum speed of the photo electrons in the two cases differ by a factor of 2. The work function of the metal (in eV) is close to : (Energy of photon =(1240)/(lambda("in nm"))Ev

Illuminating a metal surface alternately with wavelengths lambda_1 and lambda_2, when lambda_1 lt lambda_2, it is observed that corresponding ratio of maximum velocities of electrons is equal to n. Then work function of metal is

Illuminating a metal surface alternately with wavelengths lambda_1 and lambda_2, when lambda_1 lt lambda_2, it is observed that corresponding ratio of maximum velocities of electrons is equal to n. Then work function of metal is

A photoelectric surface is illuminated successively by monochromatic light of wavelength lambda and ( lambda)/(2) . If the maximum kinetic energy of the emitted photoelectrons in the second case is 3 times that in the first case, the work function at the surface of material is