The functions f R R, g: R R are defined as `f(x)={ 0`, when` x `is rational and ` 1` when `x` is irrational } and `g(x)={-1` when `x` is rational and `0 ` when `x` is irrational} find `fog(pi)` and `gof(e)`

The functions RR,g:R R are defined as f(x)={0, whenxis rational and 1 when x is irrational } and g(x)={-1 when x is rational and 0 when x~ is~ irrational}~ find~ fog (pi) and gof(e)

If f(x)={x, when x is rational and 0, when x is irrational g(x)={0, when x is rational and x, when x is irrational then (f-g) is

Two mappings f:R to R and g:R to R are defined as follows: f(x)={(0,"when x is rational"),(1,"when x is irrational"):} and g(x)={(-1,"wnen x is rational"),(0,"when x is irrational"):} then the value of [(gof)(e)+(fog)(pi)] is -

Two mappings f:R to R and g:R to R are defined as follows: f(x)={(0,"when x is rational"),(1,"when x is irrational"):} and g(x)={(-1,"wnen x is rational"),(0,"when x is irrational"):} then the value of [(gof)(e)+(fog)(pi)] is -

If the functions f(x) and g(x) are defined on R -> R such that f(x)={0, x in retional and x, x in irrational ; g(x)={0, x in irratinal and x,x in rational then (f-g)(x) is

If the functions f(x) and g(x) are defined on R rarr R such that f(x)={0,x in retional and x,x in irrational ;g(x)={0,x in irratinal and x,x in rational then (f-g)(x) is

Two functions f: R rarr R and g: R rarr R are defined by f(x) = {(0,x \ rational)(1 , x \ irrational),:}g(x)={(-1,x \ rational)(0 , x \irrational):} then g of e + fog(pi)