Consider the curve `x=1 - 3t^2.y=t-3t^3` Iftaligent at point `(1 - 3t^2.t-3t^3)` inclined at an angle `theta` positive x-axis and tangent at point `P(-2,2)` cuts the curve again at Q. The curve is symmetrical about

Consider the curve x=1-3t^(2),y=t-3t^(2) . If tangent at point (1-3t^(2),t-3t^(2)) inclined at an angle theta to the positive x-axis and another tangent at P(2,-3) cuts the cuve again at Q. The point Q will be-

Consider the curve x=1-3t^(2),y=t-3t^(2) . If tangent at point (1-3t^(2),t-3t^(2)) inclined at an angle theta to the positive x-axis and another tangent at P(2,-3) cuts the cuve again at Q. The value of tan theta+ sec theta is equal to-

Consider the curve x=1-3t^(2),y=t-3t^(2) . If tangent at point (1-3t^(2),t-3t^(2)) inclined at an angle theta to the positive x-axis and another tangent at P(2,-3) cuts the cuve again at Q. The angle between the tangent at P and Q will be-

The tangent to the curve y=x^(3) at the point P(t, t^(3)) cuts the curve again at point Q. Then, the coordinates of Q are

For the curve x=t^(2) +3t -8 ,y=2t^(2)-2t -5 at point (2,-1)

For the curve x=t^(2) +3t -8 ,y=2t^(2)-2t -5 at point (2,-1)

The curve x=1-3t^(2), y=t-3t^(3) is symmetrical with respect to -