When `K_(2)Cr_(2)O_(7)` is converted to `K_(2)CrO_(4)`, the change in the oxidation state of chromium is

When K_2 Cr_2 O_7 is converted to K_2 CrO_4 then change in the oxidation state of chromium is :

K_(2)CrO_(4) is converted to K_(2)Cr_(2)O_(7) by

When SO_(2) is passed through acidified K_(2)Cr_(2)O_(7) solution, Cr_(2)(SO_(4))_(3) is formed. The change in oxidation state of Cr is -

What is the oxidation number of chromium in K_2Cr_2O_7 ?

K_(2)Cr_(2)O_(7) overset(Delta)(to)K_(2)CrO_(4)+O_(2)+X In the above reaction X is