" (ii) "(n+2)!=2550times(n!)

If (n+2)! = 2550timesn! then the value of n is ………………….. .

Find the value of n if: (i) (n+2)! = 12n! (ii) (n+2)! = 60(n-1)! (iii) (n+3)! = 2550 (n+1)! (iv) (n-2)! = 132. (n-4)! .

(a) Compute (i) 20(!)/(18)!( ii) 10(!)/(6!.4!) (b)find n if (n+2)!=2550*n!

If (n+2)!=2550n!, then n

Find n , if (n+2)! =2550xxn !

Find n, if (n+2)!=2550xx n!(ii)(n+1)!=12xx(n-1)!

If (n+2)! =(2550)(n!), find n.

If (n + 2)! = 2550 xx n!, then the value of n is equal to