यदि `(log x)/(log 6 ) = (log 36)/(log 6 ) = (log 64)/(log y) `हो , तब `x` तथा `y` के मान बताइए।

Options

A. `8, 25`
B. `25, 8`
C. `8, 8`
D. `25, 25`

Answer

B

Explanation

प्रथम दो पद लेने पर ,
`(log x)/(log 5) = (log 36)/(log 6) = (2 log 6)/(log 6) = 2`
` rArr log x = 2 log 5 = log (5)^(2)`
` rArr log x = log 25 rArr x = 25`
अंतिम दो पद लेने पर ,
` (2 log 6)/(log 6) = (6 log 2)/(log y) rArr log y = 3 log 2`
` rArr y = 8`