` sin^(-1)`` 3/5 + sin ^(-1)`` 4/5` किसके बराबर है ?

Options

A. `pi/2`
B. `pi/3`
C. `pi/4`
D. `pi/6`

Answer

A

Explanation

दिया है , ` sin^(-1)(3/5) + sin^(-1)(4/5)`
माना ` sin^(-1)(4/5) = theta rArr sin theta = (4/5)`
` rArr cos theta = sqrt(1-sin^(2) theta)`
` rArr cos theta = 3/5`
तथा ` sin ^(-1)(4/5) = theta = cos^(-1) (3/5)`
` :. sin^(-1)(3/5)+ sin^(-1)(4/5)`
` = sin^(-1) (3/5) + cos^(-1) (3/5) = pi/2`