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[x-yquad 2x-x(1)],[2x-yquad 3x+y(1)],[x(...

[x-yquad 2x-x_(1)],[2x-yquad 3x+y_(1)],[x_(1)y_(2)])quad [=[[0,13]]],[quad " (xa "y_(1))" respectively,then "PQ=]

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If [[xy, 2x-x_ (1) 2x-y, 3x + y_ (1)]] = [[- 1,50,13]]

If [[x-y,2x-x_1],[2x-y,3x+y_1]], =[[-1,5],[0,13]] and coordinats of points P and Q be (x,y) and (x_1,y_1) respectively then P,Q=?

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