A ball is thrown up at a speed of 4.0 m/s. Find the maximum height reached by the ball. Take `g=10 m//s^2`.

Explanation

To find the maximum height reached by a ball thrown upwards with an initial speed of 4.0 m/s, we can use the equations of motion under gravity. Here’s a step-by-step solution:

### Step 1: Identify the known values
- Initial velocity (u) = 4.0 m/s (upwards)
- Final velocity (v) = 0 m/s (at maximum height)
- Acceleration (a) = -g = -10 m/s² (since gravity acts downwards)

### Step 2: Use the appropriate equation of motion
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