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A driver takes 0.20 s to apply the brake...

A driver takes 0.20 s to apply the brakes after he sees a need for it. This is called the reaction time of the driver. If he ils driving a car at a speed of 54 km/h and the brakes cause a deceleration of `6.0 m/s^2`, find the distance travelled by the car after he sees the need to put the brakes on.

Text Solution

AI Generated Solution

To solve the problem, we need to find the total distance traveled by the car after the driver sees the need to apply the brakes. This total distance consists of two parts: the distance traveled during the driver's reaction time and the distance traveled while the car is decelerating. ### Step-by-Step Solution: 1. **Convert the speed from km/h to m/s**: \[ \text{Speed} = 54 \text{ km/h} = \frac{54 \times 1000}{3600} \text{ m/s} = 15 \text{ m/s} \] ...
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A driver take 0.20 second to apply the breaks (reaction time). If he is driving car at a speed of 54 km h^(-1) and the breaks cause a decleration of 6.0 ms^(-2) . Find the distance travelled by car after he sees the need to put the breaks.

On seeing red light ahead, a driver takes 0.3 s to apply the brakes. This is called the reaction time of the driver. If he was initially driving at a speed of 36km/hr and application of the brakes causes a deceleration of 4.0m//s^(2) . Calculate the distance travelled by the car after he sees the red light.

Knowledge Check

  • A driver applies the brakes on seeing traffic singal 400m ahead. At the time of applying of brakes vehicle was moving with speed 15 m//s . The brekes provide uniform deceleration of 0.3m//s^(2) . The displacement of the vehicle in 1 mmin duration after the driver sees the singal is :

    A
    `25m`
    B
    `375m`
    C
    `360m`
    D
    `40m`

  • A person driving a car with a speed 72 km/h suddenly sees a boy crossing the road. If the distance moved by car, before the person applies brakes is 5 m, the reaction time of the person is

    A
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    B
    0.10 s
    C
    10 s
    D
    0.25 s

  • The distance travelled by a motor car in t seconds after the brakes are applied is s feet where s=22t-12t^(2) . The distance travelled by the car before it stops, is

    A
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    B
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    C
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    D
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