Figure shows a 11.7 ft wide ditch with the approach roads at and angle of `15^0` with the horizontal. With what minimum speed should a mororbike be moving on the road so that it safely croses the ditch?

Assume that the length of thebike is 5 ft, and it leaves the road when the front part runs out of the approch road.

Answer

A

Explanation

Given Horizontal range,
`= 11.7+5`
= 16.7 ft covered by the bike
`g= 9.8m/s = 32.2 ft/s^2
Now, R= (u^2 sin2alpha)/g
`u^2`= (Rg)/(sin2alpha)= (16.7xx32.2)/(1/2)
`
u= 32 ft/s`