A body of mass mis suspended by two strings making angles `alpha and beta` with the horizontal. Find the tensions in the strings.

Explanation

Take the body of mass m as the system. The fores acting on the system are
i. mg downwards (by the earth),
ii. `T_1` along the first string (by the first string ) and
`iii. T_2 along the second string (by the second string)


These forces are shown in ure. As the body is i equilibrium, these forces must add to zero. Taking horozontal components,
`T_1 cos alpha - T_2 cos beta +mg cos pi/2 =0`
`T_1 cos alpha= T_2 cos beta` .........i
Taking vertical components,
`T_1siN/Alpha+T_2sinbeta-mg=0` .............ii
ElimiN/Ating `T_2 from i and ii, `
`T_1 sin alpha + T_1(cos alpha)/(cos beta) isn beta =mg`
or , ` T_1 = mg/(sin alpha + (cos alpha)/(cos beta)sin beta=(mg cos beta)/(sin(alpha+beta))`
From i. `T_2 = (mgcosalpha)/(sin (alpha+beta)`