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A bullet moving at 250 m/s penetrates 5 ...

A bullet moving at 250 m/s penetrates 5 cm into at tree limb before comign to rest. Assuming that the force exerted by the tree limbis uniform, find its magnitude. Mass of the bulet is 10 g.

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The tree limb exerts a force on the bullet in thedirection opposite to its velocity. This force causes deceleration and hence the velocity decreases from 250 m/s to zero in 5 cm. We have to find the force exerted by the tree limb on the bullet. If a be the deceleration of the bullet, we have
`u=250 m/s, v=0, x=5 cm =0.05m,
giving, `a=((250 m/s)^2=0^2)/(2xx0.05m)=625000m/s^2`
The force on the bullet is `F=ma=6250 N.`
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