Home
Class 11
PHYSICS
The force on a particle of mass 10 g is ...

The force on a particle of mass 10 g is `(veci10 + vecj5)N`. If it starts from rest what would be its position at time `t=5s?

Text Solution

Verified by Experts

We have `F_x=10 N` giving,
`a_x=F_x/m=(10N0/(0.01 kg)= 1000 m/s^2`.
As this is a case of constnt acceleration in x-direction.
`x=u_x+1/2 a_x t^2 = 1/2 xx1000 m/s^2xx)5s)^2`
`=12500 m`
Similarly, `a_y=F_y/m=(5N)/(0.01 kg)=500 m/s^2`
and y=6250 m
Thus, the positon of the particle at t=5 s is
`vecr=(veci 12500+vecj 6250)m`.
Promotional Banner

Topper's Solved these Questions

  • NEWTON'S LAWS OF MOTION

    HC VERMA|Exercise Short Answer|17 Videos

  • NEWTON'S LAWS OF MOTION

    HC VERMA|Exercise Objective 1|14 Videos

  • NEWTON'S LAWS OF MOTION

    HC VERMA|Exercise Exercises|42 Videos

  • LAWS OF THERMODYNAMICS

    HC VERMA|Exercise Short Answer|15 Videos

  • PHYSICS AND MATHEMATICS

    HC VERMA|Exercise Exercises|34 Videos

Similar Questions

Explore conceptually related problems

The force on a particle of mass 10g is (hati 10+hatj 5) N If it starts from rest what would be its position at time t=5s ?

A time dependent force F=6t acts on a particle of mass 1kg . If the particle starts from rest, the work done by the force during the first 1 sec. will be

A time dependent force F=3t^(2)+6t acts on a particle of mass 18kg .If particle starts from rest the work done by the force during the first 3 second will be :

A force vec(F) = (40 hat (i) + 10 hat(j)) N acts on body of mass 5 kg. If the body starts from rest, its position vector vec(r) at time t = 10 s, will be

A force of (6hati+8hatj) N acted on a body of mass 10 kg. The displacement after 10 sec, if it starts from rest, will be -

A force of 10 N acts on a body of mass 0.5 kg for 0.25s starting from rest.What is its momentum now?

A particle initially at rest starts moving along x-axis.Its acceleration varies with time as a=6tm/s^(2) .If it starts from x=10m .Then the position of particle at t=2s is

A particle of mass 2kg is initially at rest. A force starts acting on it in one direction whose magnitude changes with time. The force time graph is shown in figure. Find the velocity of the particle at the end of 10s .